If a cylindrical can hold three balls with no room to spare, explain how to find the volume of the air that surrounds the balls in the can. Let the balls have a diameter of 6 inches.
can you help me @mathmale @tanya123
Wow I got tagged with mathmale...
is that bad 4 u?
Actually really Good, and sorry I'm not really good diameter...
@mathmale can you help me out please
Hello! Feels good to know that you want to work with me. I'd suggest you assume that the can has almost exactly the same diameter as do the balls: 6 inches. Suppose that the can were closed at one end, and that you fill it up with three balls. If you were to put the top on, it would touch the uppermost ball, right?
According to this reasoning: 1) Find the volume of 3 of these balls of diameter 6 inches. 2) Find the volume of the cylindrical can. 3) Subtract your result (1) from your result (2).
ok
@Abmon98 can u help me please
@gswag98: ?? Can you find the volume of a ball which is 6 inches in diameter?
ok so #1 the volume of the balls is 36 pi which is 113.0973
Three of these balls lined up in a row, touching, extend 18 inches, right? What is the volume of a cylinder of radius 3 and height 18 inches?
Remember: the diameter of the balls is 6 inches. The radius is less than that. What is the radius of each ball? What is the volume of each ball? (It's not 113.0973.)
@mathmale 162 pi the volume of the cylinder which is 508.9380099
Right on the volume of the cylinder, although you're going to need to round off that figure. For the time being, find the volume of ONE of the balls. What is the ball radius?
one of the ball's radius is 3 and the volume is 113.0973355 for one of the ball's
I agree with that. What is the total volume of the three balls?
so do I times 3 the volume of 1 ball
Summary: sphere and cylinder volumes are calculated using their radii (not their diameters). So, be certain to convert "diameter" to "radius" by halving each diameter.
Yes, you do. 3 times approx. 113.097 is what?
486 pi which is 1,526.81403
But isn't 3 times approx. 113.097 equal to 339 something? You don't need to involve pi here, as you've found that the volume of ONE ball is 113.097 and need only multiply that by 3.
oh ok
What is the total volume of the 3 balls?
the total volume of the 3 balls is 339.291 right?
yes. write that down, please: total vol. of the 3 balls is 339.291 cubic inches.
ok I did that
Now please go back and find your figure for the volume of that 6-inch-diameter, 18-inch-long cylindrical can. The can volume is .... ?
so do I do the volume of cylinder formula to get the answer
No, because we've already gone through that. All you need to do is to review this conversation and find the volume of the cylinder from way back (in the conversation).
oh ok
The can volume is .... ?
the can volume is 508.9380099
Yes, with units of measurement "cubic inches" (mandatory). OK. You have an empty cylindrical can of diameter 6 inches, radius 3 inches, and length/height 18 inches; its volume, empty, is about 308.938 cubic inches. Agree or disagree on that?
hold on I have a phone call
ok I think I agree on that
Now we put 1 ball inside the can. Will there be more or less air inside the can now?
less air
And then we put in the remaining two balls. What can you say about the volume of air still to be found inside the can?
is there a formula for volume of air
Yes and no. No specific formula! But you know the volume of the air in the can when the can has no balls in it. You also know the total volume of the three balls. So, if you put all three balls in the can, how much air is left in the can?
is the answer way back in the conversation
No. Just take the volume of the can and subtract the total volume of the 3 balls and you've got your answer. We haven't done that yet. do it now, please.
gswag98 Best Response Medals 0 the can volume is 508.9380099 mathmale Medals 1 yes. write that down, please: total vol. of the 3 balls is 339.291 cubic inches.
@mathmale the answer would be 169.64700099
You are subtracting the total volume of the balls from the volume of the empty cylinder. That is appropriate. have you forgotten something?
ok what is it supposed to be then
mathmale Medals 1 Right on the volume of the cylinder, although you're going to need to round off that figure.
mathmale Medals 1 Yes, with units of measurement "cubic inches" (mandatory).
gswag98: The volume of the air in the can, surrounding the balls, is ... ??? (round off your answer to two decimal places)
what have I forgotten
You need to round off your answer and you need to include the units of measurement. I'm not your instructor, but believe me, one of your instructors in the future is going to pick on you if you don't do both properly. Try it now.
Start with: gswag98 Best Response Medals 0 @mathmale the answer would be 169.64700099 How many decimal places would you say are reasonable? Did you use pi = 3.14, 3.14159, or 22/7? Judge what degree of accuracy seems appropriate in this situation.
Personally I'd settle for 2 decimal places, which assumes that you and I assumed that pi equals 3.14 (with two decimal places). Round off 169.67700099 to 2 decimal places, please.
thank you for your patience in sticking to this problem. I know it's been a long discussion, but still a necessary one. If you round off to two decimal places, which figure is correct? 169.67 or 169.68?
169.67
Because you have 169.677 to start with, you must round up that first 7 to an 8 because of the second 7. 169.68. 169.68 what? what are the appropriate units of measurement?
169.68 cubic inches
Beautiful. Please, review this conversation and refresh your memory on how we arrived at 169.68 cubic inches. We covered quite a few concepts here.
sorry the conversation has been so long, but I really do not see any important way in which you would have learned as much with less discussion.
Where do we stand now? Are you OK with this solution? Have any questions or comments?
Nice working with you. I'm leaving this conversation now, since I believe we're finished and you are "just looking around," according to OpenStudy. Best wishes to you.
no I'm on this conversation
I'd much rather take your word for that than OpenStudy's word!
Any comments or questions before we end this conversation?
no
Hope to work with y ou again, gswag98. Good luck!
THANK YOU @mathmale soooo much
My pleasure! Bye, gswag88. Hang in there. Over and out.
Join our real-time social learning platform and learn together with your friends!