@Aaronq
A 12.0-g plastic ball is dropped from a height of 2.50 m. Just as it strikes the floor, it is moving at a speed of 3.20 m/s. How much mechanical energy did the ball lose during its fall?

Question

@Aaronq
A 12.0-g plastic ball is dropped from a height of 2.50 m. Just as it strikes the floor, it is moving at a speed of 3.20 m/s. How much mechanical energy did the ball lose during its fall?

aaronq · Answer

At the top it's all poential energy, and right before it hits the floor it's all kinetic, so compute the PE=mgh then the KE=$\dfrac{1}{2}mv^2$ THEN subtract the KE from the PE.

aaronq · Answer

i know the wording is alittle confusing, let me clarify, $E_{loss}=mgh-\dfrac{1}{2}mv^2$

akohl · Answer

I got .233 thanks

aaronq · Answer

no probs