Question

@Aaronq
A 12.0-g plastic ball is dropped from a height of 2.50 m. Just as it strikes the floor, it is moving at a speed of 3.20 m/s. How much mechanical energy did the ball lose during its fall?

Answer 1

At the top it's all poential energy, and right before it hits the floor it's all kinetic, so compute the PE=mgh then the KE=\(\dfrac{1}{2}mv^2\) THEN subtract the KE from the PE.

Answer 2

i know the wording is alittle confusing, let me clarify, \(E_{loss}=mgh-\dfrac{1}{2}mv^2\)

Answer 3

I got .233 thanks

Answer 4

no probs