Question

Help with trig problem. Screenshot is attached!

Answer 1

@jdoe0001

Answer 2

You are given the value for 'a'. You need only concern yourself with the frequency.

370 cycles / second?

Answer 3

I don't understand

Answer 4

a = 0.12

The period of cos(x) is 2pi. 2pi/what = 370 to produce the response of one second?

Answer 5

Is it 185?

Answer 6

No. Where did the pi go?

Answer 7

\(\bf y=Acos({\color{brown}{ B}}x+C)\qquad period\to \cfrac{2\pi}{{\color{brown}{ B}}}\)

Answer 8

Its not 185pi?

Answer 9

No. Where did you get that? \(\dfrac{2\pi}{What} = 370\)

On the other hand, I think we need to change the period to 1/370th of a second. This makes the right thing to solve:

\(\dfrac{2\pi}{What} = \dfrac{1}{370}\)

Still not 185pi.

Answer 10

740pi?

Answer 11

Got it. I made that way more difficult than it was. That was my first answer but I wasn't putting it in as a model. Sorry! Thanks for your help!

Answer 12

I wasn't real clear on how to display the data. It finally dawned on me. Good work.