Question

If 2.078 g of Smarties® requires 2.11 mL of 0.250 M Na 2CO3 to reach the endpoint, how many moles of acid is
there in each gram of the candy?

Answer 1

greetings
do you understand any of this s**
sorry
but do you?
I have an equation with solution if you wanna check it over...see if it's right?

Answer 2

please do :)

Answer 3

(2 x .25 x 2.11)/3 = 3.51 moles per gram

Answer 4

Number of Moles=Concentration(mol/dm^3)*Volume(dm^3)
Moles of NaOH=2.11*0.250/1000=0.0005275
Is there any balanced equation provided that would be useful

Answer 5

umm... hold on...
(randomly flipping through lab papers)
2 HOC(CO2H)(CH2C)2H)2 + 3 NA2CO3 -> HOC(CO2^-Na^+)2 + 3 CO2 + 3H2O

Answer 6

i made a mistake Na2CO3**
look at the mole ratio of 2 HOC(CO2H)(CH2C)2H)2 to 3 NA2CO3
for every 2 moles of smarties we need 3 moles of sodium carbonate.
2:3
x:0.0005275
x=0.0005275*2/3
Number of moles=Mass(g)/Molar Mass(g/mol)
Mass is given and number of moles are given workout to get the molar mass.

Answer 7

umm...ok

so what I got from your "smarty pants science speak" was my equation was wrong, and I need to do more work

*drama queen sigh*

very well...back to the trenches I go

Answer 8

lol,i am sorry :/

Answer 9

Wait...no...hold on.
I didn't give you their equation for calculating molar acidity or whatever they call it
un momento :)

Answer 10

moles of acid = a x M x Vb

a = Reaction coefficient of the acid
Mb = Molarity of the basic solution
Vb = Volume of base used in titration converted to Liters
b = Reaction coefficient of the base

Answer 11

is that at all helpful? sorry bout that

Answer 12

i do not about this equation but looks like all your givens are provided so whats left is to plug it.

Answer 13

but i think the number moles of acid is based on the 2.078 grams of smarties not 1 gram

Answer 14

yeah...wait...
hold on

Answer 15

I don't..I don't...just look! sorry
I suck at chemistry, which makes no sense, as I love math. Chemistry just irritates the sh** out of me.

Answer 16

Calm down :)
In the link you have posted it says that smarties (citric acid)
2 HOC(CO2H)(CH2CO2H)2 + 3 Na2CO3--->HOC(CO2- Na+)(CH2CO2- Na+)2 3CO2 + 3H2O
Acid is a proton Donor and base is a proton acceptor. Citric acid consists of (CH3COOH)3
Acid+Base(Carbonate)-->Carbon Dioxide +Water+Salt
Citric Acid donates 3 H+ to form 3 moles of H2O as they will require 3OH- to accept the H+.
HOC(CO2H)(CH2CO2H)2+ we have 3 structure of CH2CO2- they are attracted to 3Na+ as the reaction progresses. thats the reason of why 3 moles of Na2CO3 are required to react with 2 moles of citric acid.
look at the balanced equation above.
2.11 mL of 0.250 M Na 2CO3 require 2.078 g of smarties to react.
In order to find the number of moles of NaOH
we use the equation Number of moles=Concentration(mol/L)*Volume(L)
We change the Volume from ml to L by dividing by 1000 to get equal units with concentration.
2.11/1000*0.250=0.0005275 moles of NaOH
From the balanced equation in order for the reaction to occur completely
it requires 2 moles of citric acid(smarties) to react with 3 moles of NaOH
what if 0.0005275 moles of Na2CO3 are used, we use mole ratio
\[2:3\]
\[x:0.0005275\]
x represent the unknown moles of citric acid. cross multiplication and you can find x easily.
\[x=0.0005275*2/3=0.0003516667 mole\]
mole per gram simply means the molar mass
Number of moles=Mass(g)/Molar Mass(g/mol)
Mass is given in your question which is 2.078 g of smarties and now you,ve got the number of moles
rearrange the equation to Molar Mass(g/mol)=Mass(g)/Number of Moles
Molar Mass(g/mol)=2.078/0.0003516667=5909.00473