Question

Suppose a lab needs to make 400 liters of a 32% acid solution, but the only solutions available to the lab are 20% acid and 65% acid. What system of equations can be used to find the number of liters of each solution that should be mixed to make the 32% solution? Let c represent the number of liters of 20% acid solution and let d represent the number of liters of 65% acid solution.

Answer 1

You just have to set up the equations,right?

Answer 2

yes

Answer 3

Ok.
Lets call the 20%= solution A
And the 65%= solution B
And the 32%= mixture

Answer 4

The basis setup would be
(liters of A x concentration of A) + ( liters of B x concentration of B)= (liters of mixture x concentration of mixture)

Answer 5

And you know there are "c" liters of A with a concentration of 20% or 0.2

Answer 6

"d" liters of B with a concentration of 0.65

Answer 7

And 400 liters of the mixture with a concentration of 0.32

Answer 8

Plug in all the given info to the setup I gave u.

0.2c + 0.65d = 0.32(400)

Answer 9

Also because the mixture is 400 liters
You would need this equation

c+d=400

Answer 10

thanks

Answer 11

youre welcome!