A .20 kg billiard ball traveling at aspeed of 15 m/s strikes the side rail of a pool table at an angleof 60 degrees. If the bll rebounds at the same speed andangle, what is the change in its momentum?

Question

anonymous · Answer

The change in momentum, delta P, equals the mass times the change in velocity, delta V.

Or $$\Delta P=M \times \Delta V$$

After you calculate delta V, you should be able to calculate your solution.