Question

FAN AND MEDAL!!

Heinz has a list of possible functions. Pick one of the g(x) functions below, show how to find the zeros, and then describe to Heinz the other key features of g(x).
g(x) = x^3 – x^2 – 4x + 4
g(x) = x^3 + 2x^2 – 9x – 18
g(x) = x^3 – 3x^2 – 4x + 12
g(x) = x^3 + 2x^2 – 25x – 50
g(x) = 2x^3 + 14x^2 – 2x – 14

Answer 1

@jim_thompson5910

Answer 2

@satellite73

Answer 3

@tkhunny

Answer 4

@Cosmichaotic

Answer 5

Which polynomial did you do? I had the option to complete one of the five I mentioned.

Answer 6

We find the zeroesby setting y = 0 or g(x) = 0, since g(x) = y and then seeing what would cause it to be 0.

The solutions (We also call them roots or zeroes), are 4, -1, and 0

Because if we were to substitute any of these values in for x, we would get 0.

Answer 7

I just did the first one.

Answer 8

g(x) = x^3 – x^2 – 4x + 4

Answer 9

Wait a sec, I factored that crap wrong heh

Answer 10

(x+2)(x-2)(x+1)

Answer 11

So the zeroes are x = -2, 2, and -1

That is where the graph crosses the x-axis in the graph.

Answer 12

So the problem asks me to show how to find the zeros. Even if its not completely accurate, can you provide me with a basic rundown of what I can show to get me by? I have to complete 12 assignments in a row by tomorrow morning at 8. Haha

Answer 13

Yea. Um, we find the zeroes by setting the polynomial equal to 0 and factoring it. Then we see what values of x will make the polynomial 0, and those are our zeroes.

Answer 14

Like if our polynomial is x^2+2x+1, then if we set it to 0 we get x^2+2x+1=0
Then if we factor we get (x+1)(x+1)=0. And if we set x = -1 then this will come out to be 0 and will work. So x = -1 is a zero of the polynomial x^2+2x+1... that's just an example hehe

Answer 15

I can explain better. I will tomorrow after I do a little more studying myself. I need to figure out how to factor higher degree polynomials and finding their 0's tonight.

Answer 16

Okay thank you!