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Calculus1 15 Online
OpenStudy (anonymous):

Integration by parts what is this final answer i can't seem to get it

OpenStudy (anonymous):

\[\int\limits_{0}^{\Pi/2} \cos(x) e^x dx\]

OpenStudy (anonymous):

not sure exactly what the final answer is i got aprox 2.47026

OpenStudy (anonymous):

@Kainui

OpenStudy (anonymous):

thank you can u help me with integration by parts \[\int\limits x(x+1)^5 dx\] what is the u = ? dv=? du=? v=?

OpenStudy (anonymous):

@ganeshie8

OpenStudy (astrophysics):

Let u = x+1 du = dx

OpenStudy (agreene):

you will need to have the parenthetical statement as a substitution.

OpenStudy (astrophysics):

No need for parts

OpenStudy (anonymous):

my online assignment is asking for u,du,dv,v though

OpenStudy (astrophysics):

Well what I usually like to do is let dv = the most complicated thing you can integrate

OpenStudy (astrophysics):

So u = ? dv = ? :P

OpenStudy (anonymous):

so is it u= x du= 1 dv= (x+1)^5 and v = (x+1)^6 ? @astrophysics

OpenStudy (astrophysics):

u = x du = dx dv = (x+1)^5 dx v = 1/6(x+1)^6

OpenStudy (anonymous):

1/6(x+1)^6-1/42(x+1)^7+c final answer?

OpenStudy (anonymous):

@Astrophysics

OpenStudy (astrophysics):

\[\frac{ x^7 }{ 7 }+\frac{ 5x^6 }{ 6 }+2x^5+\frac{ 5x^4 }{ 2 }+\frac{ 5x^3 }{ 3 }+\frac{ x^2 }{ 2 }+C\] http://www.wolframalpha.com/input/?i=integrate+x%28x%2B1%29%5E5

OpenStudy (astrophysics):

You're sort of close, u = x+1, du = dx \[\int\limits (u-1)u^5du \implies \int\limits (u^6-u^5)du\] etc, etc, \[\frac{ 1 }{ 42 }(x+1)^6(6x+1)+C\]

OpenStudy (anonymous):

thank you i got it

OpenStudy (astrophysics):

Good job :)

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