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Mathematics 13 Online
OpenStudy (larseighner):

Y'all wanna see a witch?

OpenStudy (anonymous):

Yes

OpenStudy (larseighner):

OpenStudy (the_fizicx99):

Ganeshie > Tis witch

OpenStudy (the_fizicx99):

It actually is.

OpenStudy (anonymous):

Did you see the image?

OpenStudy (ikram002p):

polar curve of the italian witch , the only curve was discoverd by a woman , cool i love it also wait ill uploud Gif to how its work

OpenStudy (anonymous):

I though it was an actually witch. I got scared for a sec there.

OpenStudy (the_fizicx99):

Smh lol.

OpenStudy (anonymous):

@ikram002p explained it.

OpenStudy (anonymous):

This is called Witch of Agnesi.

ganeshie8 (ganeshie8):

\(\large y = e^{-x^2/2}\)

OpenStudy (larseighner):

It is actually cartesian. It depends upon two variables: a and b.

OpenStudy (anonymous):

OpenStudy (ikram002p):

well , it have charastaristic equation but still one of famouse 15 special curves i guess

ganeshie8 (ganeshie8):

looks ikram did phd in polar curves :o

OpenStudy (anonymous):

Miss typed the link. http://mathworld.wolfram.com/Witchoowletnesi.html

OpenStudy (larseighner):

When a=.5 the witch becomes \( {1 \over {1+x^2}}\) better known as the derivative of arctan x.

OpenStudy (larseighner):

The general equation \[ \Large y = {{(2a)^3} \over {x^2 + (2a)^2}} \] is the way the witch is usually given.

ganeshie8 (ganeshie8):

Is the derivation easy ? Lres, in your svg file, W should be \(\large(b, a+\sin\theta)\) right ?

OpenStudy (larseighner):

@ganeshie8 Yes. This will only take a second to patch up.

ganeshie8 (ganeshie8):

i hope so, but the derivation looks hard to me still... we need to find the locus of W hmm

OpenStudy (ikram002p):

u wanna derevative of y ?

OpenStudy (ikram002p):

its like 1/x^2 formulla mm

OpenStudy (larseighner):

Revised label

ganeshie8 (ganeshie8):

sorry i don't mean derivative/differentiation.. i mean, find the equation of curve using the given constraints...

OpenStudy (ikram002p):

ohh u wanna construct the equation from the curve itself

OpenStudy (ikram002p):

well note how the change of x,y according to a,b and theta then convert to one line equation

OpenStudy (ikram002p):

the gif file well help you to note how is that happening

ganeshie8 (ganeshie8):

x = b b = OB^2 - (2a)^2

OpenStudy (ikram002p):

ok now find OB , u wanna convert to a sin theta ?

ganeshie8 (ganeshie8):

OB = OS + SB OS = \(\large \sqrt{a^2 + a^2 - 2(a)(a)\cos (90-\theta)}\) SB = \(\large \sqrt{a^2 + a^2 - 2(a)(a)\cos (\theta)}\)

OpenStudy (ikram002p):

see how its done here http://mathworld.wolfram.com/Witchoowletnesi.html

ganeshie8 (ganeshie8):

ima google this :) thats better lol

OpenStudy (ikram002p):

haha xD

OpenStudy (ikram002p):

these things woud be easy to follow the definition mm

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