Question

can someone explain how to do this ..

the discriminant for the quadratic 0=2x^2-5x+3 is/ are _______ real solutions..

Answer 1

In the quadratic equation:\[\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]
the discriminant is labeled by the:
\[b^2-4ac\]
portion

Answer 2

You have a quadratic expression in the form:
\[ax^2+bx+c\]
Where b is negative for your specific case.

Answer 3

discriminant= b^2 -4ac
from the equation a=2 ,b=-5 and c=3
now just put it in the formula and get the answer

Answer 4

omg thank you guyss.... i never thought it was this easy

Answer 5

My pleasure and the easy stuff is usually where people are less confidence, so be confident lalafeyza!