Question

integration.

Answer 1

my answer is 2/9 (3x+1) ^ 3/2 + c

Answer 2

am i right?

Answer 3

seems reasonable
you use \(u=3x+1\) ?

Answer 4

yes i did

Answer 5

That seems correct, yes

Answer 6

you are correct

Answer 7

Thank you so much guys =)

Answer 8

my answer is -1/2 ln (5-2x)^2 +c.. am i right? im not sure

Answer 9

no

Answer 10

no log here

Answer 11

yes. because i was confused with this..

Answer 12

\[\int \frac{1}{u^2}du=-\frac{1}{u}\]

Answer 13

you got the right idea, but no log for this

Answer 14

so.. what would be the next step? =)

Answer 15

clear or no?
\[\int \frac{1}{u}du=\log(u)\] but
\[\int \frac{1}{u^2}du=-\frac{1}{u}\]

Answer 16

oh yes!