Question

What is the pressure in atmospheres of 512g of N2 gas in an 12.00L container at 37.0oC ?

Answer 1

Use ideal gas equation
PV=nRT

Answer 2

p*12=(18.27)*(.297)*(37)?

Answer 3

Change 37 degree celsium to Kelvin by adding to 273
(273+37 C)=310 Kelvin
R-gas constant-0.08205746(14 L atm K−1 mol
Number of moles=Mass(g)/Molar Mass(g/mol)
N of N2=512/28=18.28 moles
P is measured in atm
P=18.28*0.0820*310/12