Question

integration. not sure of my answer

Answer 1

its 5

Answer 2

i got 1/2 sec^2 1/2x +c

Answer 3

jk its 1/2sec^2 1/2x +c

Answer 4

Is this the int?
\[\int \tan(\frac12x)\sec^2(\frac12x)dx\]

Answer 5

If it's what agreene mentioned let u = x/1, du = 1/2dx and you'll get

\[2 \int\limits \tan(u)\sec^2(u)du \]

then do another substitution for tanu