Question

if y=3/5 what is 2^2y-1 help

Answer 1

are you asking: for \[y=\frac35\]
evaluate \[2^{2y-1}\]
or
\[2^2*y-1\] ?

Answer 2

yea

Answer 3

which? \[2^{2y-1} \space\text{or}\space 2^2*y-1\]

Answer 4

the first 1

Answer 5

did u find the answer

Answer 6

So, the first thing to do is to plug simplify the equation. In this case, that cant be done.
The next step is to plug in the value for y:
\[2^{2(\frac35)-1}\]
Next we need to evaluate the exponent:
\[2^{\frac65-1}\]
I'm not a fan of fractions so I'll convert 6/5 = 1.2 and subtract the 1
\[2^{0.2}\]
or
\[2^{\frac15}\]
this cant be reduced any further

Answer 7

the answer choices is 1.15 .76 .6 1.4