Area under a curve (Calculus)
this question is innipropiate close it now
lol
l also need to include what G(x) is
\[G(x)=\int\limits_{-2}^{x}f(t)dt\]
Find the value of G(-4)
break your graph into 3 pieces 3 intervals in which you get 3 different equations
ok so I am looking for -2 to -4
my question is do I switch the limits since it should go from -4 to -2
aren't I looking for the area under the curve
\(\huge \int \limits_a^b= - \int \limits _b^a\)
so, no...don't switch the limits, add a negative sign instead
Area is 6 but I question myself
-6?
how did u get 6 ?
square of 4 units and triangle on top is 2 units
oh yes, thats correct. so Area under the curve is 6. but integral -2 to -4 will becme -6, yes correct
ok one more quick question I have to fine G(3) so that would be -2 to 3
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