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OpenStudy (precal):
Area under a curve (Calculus)
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OpenStudy (anonymous):
this question is innipropiate close it now
hartnn (hartnn):
lol
OpenStudy (precal):
OpenStudy (precal):
l also need to include what G(x) is
OpenStudy (precal):
\[G(x)=\int\limits_{-2}^{x}f(t)dt\]
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OpenStudy (precal):
Find the value of G(-4)
hartnn (hartnn):
break your graph into 3 pieces
3 intervals in which you get 3 different equations
OpenStudy (precal):
ok so I am looking for -2 to -4
OpenStudy (precal):
my question is do I switch the limits since it should go from -4 to -2
OpenStudy (precal):
aren't I looking for the area under the curve
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hartnn (hartnn):
\(\huge \int \limits_a^b= - \int \limits _b^a\)
hartnn (hartnn):
so, no...don't switch the limits, add a negative sign instead
OpenStudy (precal):
Area is 6 but I question myself
OpenStudy (precal):
-6?
hartnn (hartnn):
how did u get 6 ?
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OpenStudy (precal):
square of 4 units and triangle on top is 2 units
hartnn (hartnn):
oh yes, thats correct.
so Area under the curve is 6.
but integral -2 to -4 will becme -6, yes correct
OpenStudy (precal):
ok one more quick question I have to fine G(3) so that would be -2 to 3
OpenStudy (precal):
|dw:1405961819435:dw|
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