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Mathematics 10 Online
OpenStudy (precal):

Area under a curve (Calculus)

OpenStudy (anonymous):

this question is innipropiate close it now

hartnn (hartnn):

lol

OpenStudy (precal):

OpenStudy (precal):

l also need to include what G(x) is

OpenStudy (precal):

\[G(x)=\int\limits_{-2}^{x}f(t)dt\]

OpenStudy (precal):

Find the value of G(-4)

hartnn (hartnn):

break your graph into 3 pieces 3 intervals in which you get 3 different equations

OpenStudy (precal):

ok so I am looking for -2 to -4

OpenStudy (precal):

my question is do I switch the limits since it should go from -4 to -2

OpenStudy (precal):

aren't I looking for the area under the curve

hartnn (hartnn):

\(\huge \int \limits_a^b= - \int \limits _b^a\)

hartnn (hartnn):

so, no...don't switch the limits, add a negative sign instead

OpenStudy (precal):

Area is 6 but I question myself

OpenStudy (precal):

-6?

hartnn (hartnn):

how did u get 6 ?

OpenStudy (precal):

square of 4 units and triangle on top is 2 units

hartnn (hartnn):

oh yes, thats correct. so Area under the curve is 6. but integral -2 to -4 will becme -6, yes correct

OpenStudy (precal):

ok one more quick question I have to fine G(3) so that would be -2 to 3

OpenStudy (precal):

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