Question

What is the 35th term of the arithmetic sequence where a1 = 13 and a17 = -83?

Answer 1

you threre @campbell_st ?

Answer 2

@SolomonZelman

Answer 3

look the formula for a term in an arithmetic series is

\[a_{n} = a_{1} + (n -1)\times d\]

using the information for the 17th term you have

\[-83 = 13 + (17 - 1) \times d\]

so solve for d.

when you get d, you know the 1st term and n = 35

so substitute the information into the formula to find the 35th term

hope it helps

Answer 4

-6

Answer 5

?

Answer 6

@ganeshie8 @superhelp101

Answer 7

thats the value of d...

now go back to the formula with n = 35 and a1 = 13

substitute the value to find the 35th term

Answer 8

@camerondoherty

Answer 9

how would you set that up

Answer 10

@aum

Answer 11

well first step is you need to find the common difference..how? we let a17 be our a_n so the formula...
An=A1+(n−1)d
like i said we let A17 be An that means our n = 17

−51=13+(17−1)d


can you try solving d?

Answer 12

-6

Answer 13

\( \large
a_{n} = a_{1} + (n -1) * d \\ \large
a_n = 13 + (n-1)*(-6) \\ \large
a_{35} = 13 + (35-1) * (-6)
\)

Answer 14

to set it up its direct substitution

\[a_{35} = 13 + (35 - 1) \times -6\]

Answer 15

-191

Answer 16

yes.

Answer 17

What is the 20th term of the arithmetic sequence 3, -3, -9, ... ?

Answer 18

ok... so what is the common difference... or what is the pattern saying...?