Question

Can someone help me do this equation...
3x+6y+4z=12
Section title: equation of a plane
Chapter title: (lines and planes in space)

Answer 1

i ll try

Answer 2

okay thx in advance

Answer 3

the standard form of the equation of a line in a plane is Ax+By=C

Answer 4

z = -3/4 (x+2 y-4)

Answer 5

how did you find the answer?

Answer 6

Solving
3x + 6y + 4z = 12

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6y' to each side of the equation.
3x + 6y + -6y + 4z = 12 + -6y

Combine like terms: 6y + -6y = 0
3x + 0 + 4z = 12 + -6y
3x + 4z = 12 + -6y

Add '-4z' to each side of the equation.
3x + 4z + -4z = 12 + -6y + -4z

Combine like terms: 4z + -4z = 0
3x + 0 = 12 + -6y + -4z
3x = 12 + -6y + -4z

Divide each side by '3'.
x = 4 + -2y + -1.333333333z

Simplifying
x = 4 + -2y + -1.333333333z
if u want z then z = -3/4 (x+2 y-4)

Answer 7

thanks @gowtham89

Answer 8

would you be able to do this...

Answer 9

x=t+2
y=4t

Answer 10

section: ^Lines and planes in space: a step by step procedure