@jim_thompson5910 I have a question regarding a problem almost identical to the one you helped me with, could you help out if you have time please?
i might be able to help
It's regarding the Reimann sum method, are you familiar with it?
go for it
thanks, I was doing my work using paint so I'll upload it so you can see my work, the question I'm trying to answer is: Use a Riemann sum with five subintervals of equal length (n = 5) to approximate the area of R. Choose the representative points to be the left endpoints of the subintervals. Also, I already answered this problem for the right endpoint intervals, my question is, wouldn't using 0 or 3 end up in 0 anyway (6-2(3)) would be 0 so the right and left endpoints' sum would end up the same? Sorry if all my writing doesn't make sense =( and i can give you my answers for the right endpoint intervals that I know i got correctly
ok let me have a look
The graph looks correct for the right endpoints (see attached)
for the right endpoints, you don't compute f(0) you only compute f(0.6) f(1.2) f(1.8) f(2.4)
oh sry also f(3) as well f(3) = 0, that is correct
ok, and for the left endpoints it'd be the same minus f(3) and the addition of f(0) which is the same thing?
here's what the left endpoint graph looks like
now you are computing f(0) f(0.6) f(1.2) f(1.8) f(2.4)
5 computations because n = 5
Ok so I put those as x and then multiplied each by .6 and added them up
and got 7.2 again
you should get 7.2 for the right endpoints not the left
let me try that again
oh that's right i left out the f(0) there we go
There we go, for some reason i was thinking that if i was using 0 it automatically turned the whole thing into 0 and was skipping it over
Thanks!
what final answers did you get
I got 10.8 and then for the n=10 (which I didn't mention) I got 9.9
10.8 is correct for the left endpoints when n = 5
9.9 is correct for the left endpoints when n = 10
Thanks again!
sure thing
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