Question

Integral from 0 to 2 of: (x^3+2x^2-5x-1) / (sqrt x)

Answer 1

where are you stuck?

Answer 2

I know to do this: \[\frac{ x^4 }{ 4 } + \frac{ 2 }{ 3 }x^3 -\frac{ 5 }{ 2 }x^2 -x\]
to the top

Answer 3

And i know the bottom is just \[x ^{\frac{ 1 }{ 2 }}\]

Answer 4

NOOO!!! can't be it

Answer 5

do you multiply the top by x^2 first?

Answer 6

The integrand only:
\[\dfrac{x^3+2x^2-5x-1}{x^(1/2)}=(x^3+2x^2-5x-1)(x^{-1/2})\]
distribute it, then put the integral sign in, take it as usual.

Answer 7

can you step up?

Answer 8

I know how to distribute that, but how do you know to switch the exponent to a negative 1/2?