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Mathematics 12 Online
OpenStudy (anonymous):

The equation of the tangent line to f(x) = \sqrt{x} at x = 16 is y =? Using this, we find our approximation for \sqrt {16.3}, which is?

OpenStudy (anonymous):

@satellite73 can you please just help with one more thing? I found the approximation but for some reason on my webwork it keeps saying y=4 is wrong. would you be able to check if im right or not? please and thank you

OpenStudy (anonymous):

What's the derivative of \(\sqrt x\) at \(x=16\)?

OpenStudy (anonymous):

nvm, i figured out the answer should be y= x/8+2

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