Question

What is the 7th term of the geometric sequence where a1 = -3 and a5 = -768?

Answer 1

a5 = -768 and a1 = -3
but a5/a1 = r^4 ( r being the common ratio of the geometric sequence )

Answer 2

a5/a1 = (-768/-3) =256 = 4^4
or r^4 = 4^4
hence r= +- 4
and a7= a1 * r^6 , here you know a1 and r .......

Answer 3

now what?!

Answer 4

put the values of a1 and r to get a7
a7= a1 * r^6

Answer 5

would you do r^6 to the other side

Answer 6

when r=4
r^6 =4^6 =4*4*4*4*4*4 =1024
when r =-4

r^6 =(-4)^6 =-4*-4*-4*-4*-4*-4 =1024

Answer 7

-12,288
-3,072
12,288
3,072

Answer 8

is that the answerr