Question

a^2+ab-30b^2

Answer 1

is there a specific question ? :)

Answer 2

ive come with (a-6b)(a-5b)

Answer 3

so basically factoring x squared trinomials

Answer 4

Ohk... multiply the binomials and see if you get back the original expression

Answer 5

(a-6b)(a-5b) = ?

Answer 6

i got that as one of the answers i found including this being not factorable

Answer 7

you may check if thats correct or not by multiplying them

Answer 8

(a-6b)(a-5b) = a^2 -6ab - 5ab + 30ab
= a^2 - 11ab + 30ab

Answer 9

which is NOT same as the original expression you have started with! check ur work again

Answer 10

could it be it if i switched the signs of the first parentheses like this (a+6b)(a-5b)

Answer 11

that will work !

Answer 12

thought just didnt know whether to switch last or first sign

Answer 13

there is a standard wa of factoring this : factoring by grouping

Answer 14

a^2+ab-30b^2

find two numbers that satisfy below conditions
1) multiply to -30 \(\color{gray}{(\text{coefficient of last term is "-30"})}\)
2) add up to 1 \(\color{gray}{(\text{coefficient of middle term is "1"})}\)

Answer 15

6 and -5 are the maginal numbers :

1)(6)(-5) = -30
2) (6) + (-5) = 1

Answer 16

split the middle term using 6 and -5 :

a^2+ab-30b^2
a^2+6ab - 5ab -30b^2

Answer 17

group first two terms and last two terms,
factor the GCF

Answer 18

(a^2+6ab) + ( - 5ab -30b^2)

a(a+6b) -5b(a+6b)

(a+6b)(a-5b)

Answer 19

see if that makes more or less sense..