The graph below shows the distance (y) in kilometers of two cars from their destination at different times (x) in minutes. The table shows the values plotted on the graph: Time (in minutes) x 0 10 20 30 40 50 60 ------------------------------------------ Car 1 (in km) y 60 50 40 30 20 10 0 ------------------------------------------ Car 2 (in km) y 60 49.02438 40.05648 32.72904 26.742 21.8502 17.85318 ------------------------------------------
Part D: What is the average rate of change from x = 20 to x = 30 for the function representing the motion for car 2? What does the value of this average rate of change represent? (4 points)
I need help writing the function for Car 2, the rest I can do myself. PLEASE HELP! WILL GIVE A MEDAL!
@iGreen @SolomonZelman
Sorry this is confusing..could you take a picture of it?
Ya there's a graph for it
Sorry I didn't post that earlier :|
Hmm..the y-intercept is 60.
yes this is what I got so far, because I think it should be an exponential function: f(x) = 60(b)^x
Yeah it's definitely exponential..
I just don't what b is. I know b is the base of the exponential function and it models the change that is happening.
Yes..
Okay it's gonna be.. f(x) = 60(0.98^x)
Can you explain how you got 0.98?
Slope from (0, 60) and (2, 40) is approximately 0.98. (Using the slope formula)
You will see the exact same graph.
Need help with Part D?
No, but thx with everything!!!!!!!!!!
Will u be here if I need help with another question?
Yep.
THX.... I luv u! I actually don't really luv u(like that) but u know.........
as a friend
-.-
Lel
Btw, do you do FLVS?
I'm pretty sure you do..
Yup
'Cause I remember this stuff..
Algebra I?
Did u take FLVS or are u taking it?
I'm still taking FLVS, that's my school. But I've already finished Algebra I..
are u still there @iGreen , because I think I need help with the average rate of change, since, I got a negative decimal
Okay.
\[\frac{ f(b)-f(a) }{ b-a }= \frac{ 40.05-32.72 }{ 20-30 }= \frac{ 7.33 }{ -10 }\]
that doesn't even make sense
so maybe I did something wrong?..............
What is the average rate of change from x = 20 to x = 30 for the function representing the motion for car 2? This is the formula: \(m = \dfrac{y_2-y_1}{x_2-x_1}\) Points: \((20, 40), (30, 32.73)\) \(y_2 = 32.73\) \(y_1 = 40\) \(x_2 = 30\) \(x_1 = 20\) Plug it in the formula: \(m = \dfrac{32.73-40}{30-20}\) Simplify: \(m = \dfrac{-7.27}{10}\) \(m = -0.727\)
It's supposed to be negative..because the slope is also negative..
@Chocolate1031
oh I see, I forgot that formula.......... I LIKE ALWAYS DO, MY DAD KEEPS ON TELLING ME
I am wierd
@iGreen
Lol
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