A large emerald with a mass of 812.04 grams was recently discovered in a mine. If the density of the emerald is 2.76grams over centimeters cubed, what is the volume? Round to the nearest hundredth when necessary and only enter numerical values, which can include a decimal point.
help plz
@phi @satellite73 @AravindG
@Compassionate @iambatman @thomaster
write down what you know \[ 2.76 \frac{\text{g}}{\text{cc}} \] 812.04 g notice if we multiply by a factor K that has units cc/g we would have \[ 812.04\ \cancel{g} \cdot K \frac{cc}{\cancel{g}} = K\cdot 812.04\]
* \(K \cdot 812.04 \) cc so you need to find a factor that has units of cc/g that you can multiply by. any idea what that factor is ?
@phi my internet cut sorry
@phi 2.76
first, in these kinds of problem *always* include the units we know 2.76 g/cc but we want cc/g any ideas what to do ?
Uh so maybe 812.04?
812.04 g we want cc/g
sorry bit lost
notice this \[ \frac{1}{2.76 \frac{g}{cc} }\] if we multiply top and bottom by cc we get \[ \frac{1\cdot cc}{2.76 \frac{g}{\cancel{cc}} \cdot \cancel{cc}} = \frac{1}{2.76} \frac{cc}{g} \]
@ganeshie8
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