Question

: |y + 3| < 9

Answer 1

-12 < y < 6


y = 12 and -12


-9 < y < 9


-6 < y < 6

Answer 2

Okay, I think the answer is D..

Answer 3

No wait it's A.

Answer 4

thanks i second guess my self on it i thought it was a to

Answer 5

\(|y + 3| < 9\)

You have to solve this two different ways:

\(y + 3 < 9\)

And

\(-y - 3 < 9\)

------------------------

\(y + 3 < 9\)
\(y < 6\)

------------------------

\(-y - 3 < 9\)
\(-y < 12\)
\(y > -12\)

So A is your answer.

Answer 6

Welcome to Open Study!

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Answer 7

Solve: |r| - 12 > 23


r >35 or r< -35


r < 11 or r > -11


No solution


r > 35

Answer 8

@iGreen

Answer 9

@iGreen

Answer 10

Um, you should make a new question..just close this.

Answer 11

But anyway:

|r| - 12 > 23

If the absolute values(| signs) are around one value, it makes it positive, that's all.

r - 12 > 23

Add 12:

r > 35