Quadratic formulas anybody???? PLEASE!!

Question

anonymous · Answer

@vishweshshrimali5

vishweshshrimali5 · Answer

$$\large{x = \cfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}}$$

For:

$$\large{ax^2+bx + c = 0}$$

This is the general quadratic formula

anonymous · Answer

were you trolling on the last post , i am serious

anonymous · Answer

trolling?

vishweshshrimali5 · Answer

There are some important identities as well:

1. $\large{(x+y)^2 = x^2 + 2xy + y^2}$

2. $\large{(x-y)^2 = x^2 - 2xy + y^2}$

3. $\large{(x+y+z)^2 = x^2 + y^2 + z^2 + 2(xy + yz + xz)}$

and some more

vishweshshrimali5 · Answer

Any particular formula you are looking for ?

anonymous · Answer

$$3^{2}+5x+1=0$$

anonymous · Answer

i dont know how to work through it

vishweshshrimali5 · Answer

Is this the question:

$$\large{3x^2 + 5x + 1 = 0}$$

anonymous · Answer

yes

vishweshshrimali5 · Answer

Good

Then you can use this formula directly:

$\color{blue}{\text{Originally Posted by}}$ @vishweshshrimali5
$$\large{x = \cfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}}$$

For:

$$\large{ax^2+bx + c = 0}$$

This is the general quadratic formula
$\color{blue}{\text{End of Quote}}$

anonymous · Answer

ok

vishweshshrimali5 · Answer

So, can you compare both equations and find out a, b and c ?

anonymous · Answer

isnt it just one whole equation tho??

vishweshshrimali5 · Answer

No I meant compare the following equations:

$$\large{ax^2 + bx + c = 0}$$

$$\large{3x^2 + 5x + 1 = 0}$$

What are a, b and c ?

anonymous · Answer

where do i find b and ac???

anonymous · Answer

ohh ok now i get it

vishweshshrimali5 · Answer

Good :)

anonymous · Answer

wait so is the answer $$x-3x ^{2}\pm \sqrt{5x ^{2}}-4x ^{2}1$$

anonymous · Answer

$$2x$$

vishweshshrimali5 · Answer

Why ?

anonymous · Answer

idk i just tryed... ;(

vishweshshrimali5 · Answer

Its okay.. 

First tell me what are a,b and c ?

anonymous · Answer

a=3 b=5 c=1

vishweshshrimali5 · Answer

Great !

vishweshshrimali5 · Answer

So now lets plug in the values in this equation:

$\color{blue}{\text{Originally Posted by}}$ @vishweshshrimali5
$$\large{x = \cfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}}$$

$\color{blue}{\text{End of Quote}}$

vishweshshrimali5 · Answer

What will we get ?

anonymous · Answer

$$-5\pm \sqrt{5^{2}}-4*3*1                   \over 2*3$$

vishweshshrimali5 · Answer

It is this :

$$\large{\cfrac{-5 \pm \sqrt{5^2 - 4*3*1}}{2*3}}$$

Correct ?

See the square root covers the whole $\large{b^2 - 4ac}$

anonymous · Answer

$$-5\pm \sqrt{13}                      \over 6 $$

anonymous · Answer

yayi got it right!!!

vishweshshrimali5 · Answer

Great !

anonymous · Answer

yup it was hard tho...

vishweshshrimali5 · Answer

But good to see that you got it !!

Great going :)