Question

A triangle has vertices at (2, 4), (-3, -6), and (4, -2). Find its perimeter rounded to two decimal places

Answer 1

Hint: use distance formula between two points:
\(\huge √{(x_2-x_1)^2+(y_2-y_1)^2}\)
for each of the three sides. Add lengths to get perimeter.

Answer 2

thanks

Answer 3

You're welcome! :)
Here's a correct version of the formula, just in case:
\(\huge \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\)

Answer 4

kk

thanks