Question

Write the standard equation of the circle with center (2, 3) and a diameter of 12.

Answer 1

@mathstudent55

Answer 2

Hi give me a min

Answer 3

(x-2)^2+(y-3)^2=6
this is because the equation is (x-h)^2+(y-k)^2=r

Answer 4

h is the x point

Answer 5

k is the y point and the r is the raidus

Answer 6

go it?

Answer 7

yes thank you! can I ask you another question?

Answer 8

sure make another post

Answer 9

1. The equation of a circle is (x + 7)2 + (y + 2)2 = 49. Determine the length of the diameter.


2. The equation of a circle is (x + 3)2 + (y + 7)2 = 25. Where is (3, 4) located in relation to the circle?
Answer

A. On the circle

B. In the interior of the circle

C. In the exterior of the circle

D. at the center of the circle

I had 2 questions lol

Answer 10

1. Since 49 is the radius to find the diameter it is just 49*2

Answer 11

Number 1 only gives me the anwsers


A. 7

B. 49

C. 9

D. 14

Answer 12

hold on

Answer 13

silly me the last part is r^2

Answer 14

so it is √(49)*2

Answer 15

so 7?

Answer 16

also the first question is 36 not 6

Answer 17

no since 7 is the radius

Answer 18

the diameter is r*2 so it is 14

Answer 19

also remember the first question that i did with you it is not 6 it is 36 for r

Answer 20

okay thank you! what about the other question I asked?

Answer 21

ok give me a second

Answer 22

i was going to draw it

Answer 23

ok

Answer 24

so the a is the (3,4)

Answer 25

so that would make it interior b/c its smaller then (3,7)?

Answer 26

the circle is negative because the circle equation is (x-h)^2+(y-h)^2=r^2 not (x+h)^2+(y+h)^2=r^2

Answer 27

then exterior?

Answer 28

no it would be exterior since it is outside of the circle

Answer 29

ohh i get

Answer 30

thank you!

Answer 31

ok gtg have a good day

Answer 32

Np