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Mathematics 20 Online
OpenStudy (anonymous):

@KIOwNIOvE

OpenStudy (anonymous):

What are the factors of 3x^2 + 10x - 8?

OpenStudy (anonymous):

@Elsa213 @ganeshie8 @mathstudent55 @kohai

OpenStudy (anonymous):

@thomaster @mathstudent55 @iGreen

OpenStudy (anonymous):

@Brainybeauty

OpenStudy (anonymous):

@Squirrels

OpenStudy (anonymous):

The equation is\[3x ^{2} + 10x - 8\]

OpenStudy (squirrels):

Ok, well that equation is written in quadratic form \[ax^2+bx-=0\]

OpenStudy (squirrels):

Are you familiar with the quadratic equation?

OpenStudy (anonymous):

No :/

OpenStudy (squirrels):

Ok this is the quadractic equation \[x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]

OpenStudy (anonymous):

Alright

OpenStudy (anonymous):

The roots are \[x = \frac{ -b \pm \sqrt{b ^{2} - 4ac} }{ 2a}\]

OpenStudy (squirrels):

\[ax^2+bx-c=0\] \[3x^2+10x-8=0\]

OpenStudy (anonymous):

Right

OpenStudy (anonymous):

\[= \frac{ - 10 \pm \sqrt{100 - 4*3*(-8)} }{ 2*3 }\]

OpenStudy (squirrels):

Now you must plug those numbers into the quadratic equation

OpenStudy (squirrels):

Brainy, you should let him try it out, but yes that's correct.

OpenStudy (anonymous):

yeah

OpenStudy (squirrels):

I'm pretty sure you can figure out the rest @LearningIsAwesome Just find both cases and those are your factors.

OpenStudy (anonymous):

\[\frac{ -10 \pm \sqrt{196} }{ 6}\]

OpenStudy (anonymous):

You want the rest of the answer? @LearningIsAwesome

OpenStudy (squirrels):

@Brainybeauty do not give him the answer. Let him figure this out himself

OpenStudy (anonymous):

oh okay

OpenStudy (anonymous):

@LearningIsAwesome If you want I can tell you how this equation was made

OpenStudy (squirrels):

I kinda already told him, if you scroll up ^^^^ lol

OpenStudy (anonymous):

Where do I go from there? I am like in the dark here

OpenStudy (anonymous):

Yeah but I can tell the steps on how the quadratic equation came if he wants.

OpenStudy (anonymous):

Ok let me tell you

OpenStudy (anonymous):

\[= \frac{ -10 + 14 }{ 6 } or \frac{ -10 -14 }{ 6}\]

OpenStudy (anonymous):

Okay... then what?

OpenStudy (anonymous):

Yeah just a minute

OpenStudy (anonymous):

\[= \frac{ 4 }{ 6 } ~ or ~ \frac{ -26 }{ 6 }\]

OpenStudy (anonymous):

\[= 2/3 ~ or -13/3\]

OpenStudy (anonymous):

Done @LearningIsAwesome

OpenStudy (anonymous):

(3x - 8)(x + 1) (3x - 1)(x + 8) (3x - 4)(x + 2) (3x - 2)(x + 4) these are my options...

OpenStudy (anonymous):

yeah so to find the factors, just subtract the factors from x

OpenStudy (anonymous):

\[The~factors~are~ x-2/3 ~ and ~ x- (-13/3)\]

OpenStudy (anonymous):

So you just multiple them and get \[(x-2/3)(x+13/3)\]

OpenStudy (anonymous):

Is that it?

OpenStudy (squirrels):

@Brainybeauty, I told you not to give the answer -_-

OpenStudy (anonymous):

Sorry @Squirrels @LearningIsAwesome I went wrong somewhere correct it you will get the answer

OpenStudy (anonymous):

I still just don't understand

OpenStudy (squirrels):

Have to go write now. Sorry. And @LearningIsAwesome pay attention to our teachings instead of trying to get the answer. Bai bai for now

OpenStudy (anonymous):

I AM!

OpenStudy (anonymous):

But I don't get it!

OpenStudy (anonymous):

:/...

OpenStudy (anonymous):

@LearningIsAwesome If you want I can tell you how to solve this

OpenStudy (anonymous):

Yes please T-T

OpenStudy (anonymous):

Ok so you want to know how that equation came?

OpenStudy (anonymous):

No...

OpenStudy (anonymous):

so?

OpenStudy (anonymous):

Can you tell me how to solve this? :/

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

Yay!

OpenStudy (anonymous):

:) There's not much to do You just have to put the values of a, b and c in the quadratic equation and solve

OpenStudy (anonymous):

so in the equation\[3x ^{2} + 10x - 8\] a is 3 b is 10 and c is (-8)

OpenStudy (anonymous):

Now put those values in the equation I told you above

OpenStudy (anonymous):

got it? @LearningIsAwesome

OpenStudy (anonymous):

I got it, I'm just gonna take a break my head's kinda spinning now and I'll just come back to it later ^^

OpenStudy (anonymous):

Yeah! Try it once you will get it! And if you have any doubts just tell me I will try to help out! :) It will be very easy once you understand it well :)

OpenStudy (anonymous):

You can always medal me back brah :P ahhahaha

OpenStudy (anonymous):

lol ok

OpenStudy (anonymous):

Yes! 8 more til my title O.O

OpenStudy (anonymous):

yeah! :)

OpenStudy (anonymous):

cool

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