Question

How in the world am I supposed to solve for x?
a(bx+2)=cx-12

Answer 1

hold on

Answer 2

@jagr2713 please help me with my problem

Answer 3

Divide each term in the equation by (bx+2).
Divide each term in the equation by (bx+2).

a(bx+2)/bx+2=cx/bx+2−12/bx+2

Answer 4

Reduce the expression by canceling out the common factor of (bx+2) from the numerator and denominator.

a (bx+2)/ (bx+2) =cx/bx+2−12/bx+2


Reduce the expression by canceling out the common factor of (bx+2) from the numerator and denominator.

a=cx/bx+2−12/bx+2


Combine all similar expressions in the polynomial.

a=cx−12bx+2

Answer 5

you get it?

Answer 6

You know I'm solving for x. Right?

Answer 7

Cuz, it doesn't seem like you solved for x.

Answer 8

lol i sloved for a hold on let me type it

Answer 9

its long can i just give answer?

Answer 10

Multiply a by each term inside the parentheses.
Multiply a by each term inside the parentheses (bx+2).

a(bx)+a(2)=cx−12


Multiply a by the bx inside the parentheses.

a⋅bx+a(2)=cx−12


Multiply a by bx to get abx.

abx+a(2)=cx−12


Multiply a by the 2 inside the parentheses.

abx+a⋅2=cx−12


Multiply a by 2 to get 2a.

abx+2a=cx−12

Answer 11

Since cx contains the variable to solve for, move it to the left-hand side of the equation by subtracting cx from both sides.
abx+2a−cx=−12
Factor out the GCF of x from each term in the polynomial.

Answer 12

Factor out the GCF of x from the expression abx.

x(ab)−cx=−2a−12


Factor out the GCF of x from the expression −cx.

x(ab)+x(−c)=−2a−12
x(ab)+x(−c)=−2a−12
Factor out the GCF of x from abx−cx.
x(ab−c)=−2a−12
Divide each term in the equation by (ab−c).

Answer 13

divide each term in the equation by (ab−c).

x(ab−c)/ab−c=−2a/ab−c−12/ab−c
Reduce the expression by canceling out the common factor of (ab−c) from the numerator and denominator.

x (ab−c) /(ab−c) =−2a/ab−c−12/ab−c
Reduce the expression by canceling out the common factor of (ab−c) from the numerator and denominator.

x=−2a/ab−c−12/ab−c


Combine all similar expressions in the polynomial.

x=−2/a−12/ab−c
Factor out the GCF of −2 from the expression −2a.

x=−2(a)−12/ab−c


Factor out the GCF of −2 from the expression −12.

x=−2(a)−2(6/)ab−c


Factor out the GCF of −2 from −2a−12.

x=−2(a+6)/ab−c


Remove the parentheses from the numerator.

x=−2(a+6/)ab−c

Answer 14

you get it

Answer 15

I don't have any of that as my answer choice. Here's what it is:
A. x=(-12-2a)/(ab-c);ab≠c
B. x=(-12+2a)/(c+ab);ab≠c
C. x=(2a+12)/(c-ab);no restrictions
D. x=(ab-c)/(-12-2a);a≠-1

Answer 16

wow idk sorry

Answer 17

a(bx+2)=cx-12
abx+2a=cx-12
abx-cx=-2a-12
x(ab-c)=-2a-12
x=(-2a-12)/(ab-c)

Answer 18

It's ok, jagr. At least you tried:D Gave it a shot:D

Answer 19

=(-12-2a)/(ab-c)

Answer 20

I think it should be A
The answer you got was: x=−2(a+6/)ab−c
That would be (-2a-12)/(ab-c) if you distribute the 2; then change the order of the terms in the numerator: (-12-2a)/(ab -c) because that would be an equivalent expression

Answer 21

And, of course ab can't equal c, because if it did you would be dividing by 0 ;)

Answer 22

Ok. So what is it? I need an explanation. I don't really understand this. Everyone has different answers and I don't even have a clue who to go with.

Answer 23

this is an confusing question lol

Answer 24

Jagr's answer is correct. However, it doesn't "appear" to show up in your list of choices - but actually it does.

Answer 25

Here is why. You got the answer x = -2(a + 6)/(ab - c)

Answer 26

If you distribute the -2 in the numerator, you get the equivalent expression (-2a -12)/(ab-c)

Answer 27

You can then use the commutative property of addition on the numerator as well, to get another equivalent expression: (-12-2a)/(ab-c)

Answer 28

So that answer is actually the "same" as the one you got, it just looks a bit different!

Answer 29

Lol, Let me ask @ganeshie8 . Lets see what he says.

Answer 30

Sure! :D

Answer 31

@YanaSidlinskiy what do you not understand about my solution
its only a few steps so let me know which part confuses you

Answer 32

\(a(bx+2)=cx-12 \\abx+2a=cx-12 \\abx-cx=-2a-12 \\x(ab-c)=-2a-12 \\x=\frac{-12-2a}{ab-c}\)

Answer 33

Why are you subtracting cx in the third step? How come you moved all the numbers to the right and variables to the left?

Answer 34

we want to get all the terms with x on one sides and all the other terms on the other, so that we can isolate x

Answer 35

Oh......Ok..Thank you soooooooooo much:D

Answer 36

np

Answer 37

Nice zz

Answer 38

Oh, shoot! Forgot to say \(\huge\cal\color{lime}{Thank~you!!!}\) to everyone who replied and tried to help me out!!:D Thanx again!!:D

Answer 39

yw lol

Answer 40

Wlcm :) Have a good afternoon!

Answer 41

Hahha:D Thanx anteater:D you too:D