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Mathematics 11 Online
OpenStudy (australopithecus):

Hypothesis Testing: Determining the smallest Significance at which you would be willing to reject the null hypothesis of the following data Null hypothesis (H_o) mean =/= 3500 Hypothesis (H_1) mean = 3500 The range I have determined where we would reject the null hypothesis is: (3501.5, 3498.5) Not sure if I'm doing this right, question is below: i.imgur.com/9d64xhE.png

OpenStudy (australopithecus):

I got 0.928 for my significance level seems kind of high

OpenStudy (australopithecus):

This is essentially saying that 92.8% of my given sample size will reject the null hypothesis when it is true. Which is pretty awful.

OpenStudy (anonymous):

Are you sure about the \(=/\not=\) designation? Usually the null hypothesis takes on a specific value for the statistic in question, and the alternative says otherwise.

OpenStudy (australopithecus):

Yes

OpenStudy (australopithecus):

https://i.imgur.com/nTb6fA6.png This is the question

OpenStudy (anonymous):

Hmm, I'm not convinced that \(\mu=3500\) isn't the null hypothesis. Consider the test statistic for a \(Z\) test, or maybe a \(T\) test, considering the sample size. \[Z=\frac{\bar{x}-\mu_0}{\sigma/\sqrt n}~~\text{or}~~T=\frac{\bar{x}-\mu_0}{s/\sqrt n}\] \(\mu_0\) is an assumed value for the mean, taken from the null hypothesis, so the test statistic would be \[Z(\text{or }T)=\frac{3450-3500}{60/\sqrt{12}}\] If the null hypothesis was \(\mu\not=3500\), you wouldn't have a value to use for \(\mu_0\).

OpenStudy (australopithecus):

Thanks for the help I appreciate it immensely

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