A parabola has a vertex at (4, 0) and passes through the point (6, 1). Which of the following is the equation of this parabola in the form 2003-18-03-00-00_files/i0230000.jpg?

Question

anonymous · Answer

help please

anonymous · Answer

The following work represents an attempt to find the equation of the parabola which has a vertex of (0, 0) and passes through the point (1, 3). Is the work correct? If not, what is the error?

2003-18-03-00-00_files/i0240000.jpg

anonymous · Answer

will give medal

anonymous · Answer

and fan

anonymous · Answer

Well, if the vertex is at (4,0), we can plug in to the standard form like this$$y=a(x-h)^2+k=a(x-4)^2+0=a(x-4)^2$$Now substitute (x,y)=(6,1) to solve for a.

anonymous · Answer

That goes like this$$1=a(6-4)^2=4a \implies a=\frac{1}{4}$$

anonymous · Answer

That, in turn, means your function is$$y=\frac{1}{4}(x-4)^2=\frac{x^2}{4}-2x+4$$

anonymous · Answer

Do math every day.