Question

HELP!!!
Solve by completing the square.

x² - 2x - 24 = 0

Answer 1

x² - 2x - 24 = 0
x² - 2x+1-1-24=0 (adding and subtracting 1)
\[(x-1)^{2}-25=0\]
\[(x-1)^{2}=25\]
\[(x-1)^{2}=5^{2}\]
x-1=5
x=6

Answer 2

also
x-1= -5
x=-4

Answer 3

What does that make the aswer

Answer 4

when we remove square root absolute(mod) function come
as 3\[3^{2}=9 also (-3)^{2}=9\]