Find a power series representation of the function \(f(x) =\large \frac{x}{2x^2+1}\)
@satellite73 @ganeshie8 @mathstudent55
they are doing these things where they are putting these in the form \(\frac{a}{1-r}\)m and then putting them into geometric sums. But I cant figure out how to do it with this one.
For |x| < 1, \[\large \frac{1}{1-x} = \sum_{n=0}^{\infty} x^n,~~~~~~|x| \lt 1 \\ \large \frac{x}{2x^2+1} = \frac{x}{1-(-2x^2)} = x * \sum_{n=0}^{\infty} (-2x^2)^n = \sum_{n=0}^{\infty} (-2)^nx^{2n+1} \]
The second line above is the standard sum of an infinite geometric series: 1 + x + x^2 + x^3 + .... = 1 / (1-x) for -1 < x < 1 For the given problem, the interval of convergence is: \( \large |-2x^2| < 1 \\ \large -\frac{\sqrt{2}}{2} \lt x \lt \frac{\sqrt{2}}{2} \)
asdf_movie
hi girl
hi samsonite
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i knew that
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naw jk can u help me
math pre al
Which graph shows the solution for the inequality|dw:1406070803459:dw|
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