find the derivative of the hyperbolic of 1/4sinh(2x)-x/2, i know i have to use the product rules but i am confused on what to use with the product rule

Question

anonymous · Answer

not sure if you mean( 1/4(sinh 2x))   - (x/2)
If yes it's( (1/2) cosh (2x)) - (1/2)

anonymous · Answer

$$\frac{ 1 }{ 4 }\sinh(2x)-\frac{ x }{ 2 }$$ this is what it is, and it is a hyperbolic derivative

anonymous · Answer

Yes then that is the answer. Disecting the problem:
$$\frac{ 1 }{ 4} \sin h ( 2x) = \frac{ 1 }{ 4 } ( 2) \cos h (2x)$$
and d/dx of - x/2 = 1/2 so the answer :
$$\frac{ 1 }{ 2  } \cos h (2x) - \frac{ 1 }{  }$$

anonymous · Answer

-1/2 *

anonymous · Answer

uhhh, the book says sinh^2(x)

anonymous · Answer

Are you sure? I even checked with an online calc to make sure all my work is right. By no means should you use this tool to solve all probs lol http://www.derivative-calculator.net/#expr=1%2F4%20sinh%20%282x%29%20-%20x%2F2

anonymous · Answer

click go

anonymous · Answer

it might be major simplifcation your answer is probabaly right