@Abhisar
A 51-g rubber ball is released from rest and falls vertically onto a steel plate. The ball strikes the plate and is in contact with it for 0.5 ms. The ball rebounds elastically and returns to its original height. The time interval for the round trip is 3.00 s. What is the magnitude of the average force that the plate exerted on the ball?

Question

@Abhisar 
A 51-g rubber ball is released from rest and falls vertically onto a steel plate. The ball strikes the plate and is in contact with it for 0.5 ms. The ball rebounds elastically and returns to its original height. The time interval for the round trip is 3.00 s. What is the magnitude of the average force that the plate exerted on the ball?

akohl · Answer

Do you know what equation to use to solve

anonymous · Answer

This seems like not only a collision problem but also an impulse problem.
Impulse = Average Force x Time

akohl · Answer

How do I get the avg force

anonymous · Answer

Conservation of momentum.
Force = Mass x Acceleration.

Also,
Impulse = Average Force x change in Time
Since 
$$F = ma$$
and $$a = \frac{ \Delta v }{ \Delta t }$$
then 
$$Impulse = m \Delta v$$

akohl · Answer

I got 1500n u

anonymous · Answer

I did not perform the operation but the conservation of momentum applies here since you are given an elastic collision.
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