Question

I just want to make sure this equation is right.

Answer 1

\[-\sqrt{x}=-1\]

Answer 2

I have to solve for x. And i got 0 but, when i plug it in I dont get -1.

Answer 3

\(\bf -\sqrt{x}=-1\implies -1\cdot \sqrt{x}=-1\implies \sqrt{x}=\cfrac{\cancel{ -1 }}{\cancel{ -1 }}\implies \sqrt{x}=1
\\ \quad \\
(\sqrt{x})^2=(1)^2\implies \sqrt{x^2}=1^2\implies ?\)

Answer 4

First divide both sides by -1 to get

\[\Large -\sqrt{x}=-1\]

\[\Large \frac{-\sqrt{x}}{-1}=\frac{-1}{-1}\]

\[\Large \sqrt{x} = 1\]

Answer 5

What's next?

Answer 6

\[(\sqrt{x})^2 \]and the square root and the ^2 cancel eachother making it X=1

Answer 7

I see what i did wrong. I didnt divide it.

Answer 8

very good, you nailed it

Answer 9

Thank you @jim_thompson5910

Answer 10

you're welcome