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Write x2 - 6x + 7 = 0 in the form (x - a)2 = b, where a and b are integers.
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for \(x^2+bx+c=0\) we have \((x-\frac{-b}{2})=(\frac{b}{2})^2-c\)
?
do you see that if you know what b and c are you can use that form to get the answer?
oh. thx
so for you b = -6, and c = 7
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sorry, i don't get how i solve with the x
hold on...
i got 21... i did it wrong
\((x-\frac{-(-6)}{2})^2=(\frac{6}{2})^2-7\)
\((x-3)^2=2\)
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you are not trying to get a number....reread the question.
oh. no, u got it. thank you so much :)
i get it now. thx
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