Question

Help!

Answer 1

Note that \(\large \sqrt{r^6s^{11}} = \sqrt{r^6s^{10}s}=\sqrt{r^6}\sqrt{s^{10}}\sqrt{s} \)

What do you get when you simplify things now? :-)

Answer 2

i only get how to get r^3 but not the rest

Answer 3

i am more then likely that it is c though

Answer 4

The thing that we need to remember is that in exponential form, \(\large \sqrt{x}=x^{1/2}\). So, in this case, we would see that \(\large \sqrt{r^6} = (r^6)^{1/2}\). By the exponent properties, this is equivalent to \(\large r^{6/2} = r^3\). Thus, \(\large \sqrt{r^6}=r^3\). In a similar way, we see that \(\large \sqrt{s^{10}} = (s^{10})^{1/2} = s^{10/2} = s^5\). Thus, \(\large \sqrt{r^6}\sqrt{s^{10}}\sqrt{s} = r^3s^5\sqrt{s}\).

Does this make sense? :-)

Answer 5

oh wow yeah it does! Thank you so much do you think you can help me with some other questions?

Answer 6

Sure, that'd be fine.

Answer 7

that one and this one

Answer 8

For the first one, I assume you're solving for x? If so, you'll want to rewrite the equation \(\large m^{7/9} = \sqrt[14]{m^x}\) in terms of exponents (assuming I read that first exponent properly...it looks like a 7/9 to me at least). To do this, you'll need to recall that \(\large \sqrt[n]{x} = x^{1/n}\). So in this case, we see that \(\large \sqrt[14]{m^x} = (m^x)^{1/14} = m^{x/14}\) and thus \(\large m^{7/9} = m^{x/14}\) implies that \(\dfrac{7}{9} = \dfrac{x}{14}\). However, I don't see the solution \(x=\dfrac{98}{9}\) as an option for you to pick. Furthermore, if we were to solve for m, we really can't since we're not told what x is....so, this is a bad problem in my opinion, unless I completely misread that first exponent. >_>

For the second one, the number of students that like both soccer and tennis is 30, so I would say that the relative frequency is 30/100 = .30.

Answer 9

wow that makes a lot of sense omg. thank you so much!!

Answer 10

Glad to hear! I would clarify that first one with your teacher, though. :-)