Question

find the equation of the quadratic function with roots -6 and -4 and through the point (4,40) ...medal provided

Answer 1

To find the equation, multiply the roots, which are (x+6)(x+4). That comes to\[x ^{2}+10x+24\]

Answer 2

Now we have to worry about the point (4,40).

Answer 3

Line of symmetry is x = -5...

Answer 4

a(x+6)(x+4)=y
plug in (-6,-4)
solve for a

Answer 5

why plug in (-6,-4)?

Answer 6

Do you mean a(4+6)(4+4)=40 and solve for a?

Answer 7

The point (4,40) needs to go in there, doesn't it?

Answer 8

I get that a = .5

Answer 9

yes I did

Answer 10

sorry

Answer 11

So it is \[.5(x ^{2}+10x+24)\]

Answer 12

or as mathematicians say (1/2)(x^2+10x+24)

Answer 13

:P

Answer 14

are you an engineer @IMStuck ?

Answer 15

Which gives us:\[.5x ^{2}+10(.5)x+24\]which is\[\frac{ 1 }{ 2 }x ^{2}+5x+24=y\]

Answer 16

No...not an engineer...high school math is my thing! Teacher, dontcha know?!

Answer 17

You're way way smarter than I am, @zzr0ck3r !!!!!

Answer 18

engineers love decimals

Answer 19

lol that has nothing to do with it

Answer 20

and I doubt it.

Answer 21

@IMStuck how do you know what the line of symmetry is?

Answer 22

Well the line of symmetry is exactly halfway between the x intercepts. Since this is an x^2 parabola, the graph opens upward and the x point halfway between -6 and -4 is -5.

Answer 23

@IMStuck ohh.. like the equation x+x/ 2 ...

Answer 24

@IMStuck so then howd you get .5(x2+10x+24)