Solve x2 + 5x = -6.
x = 5 and x = 1 x = -5 and x = -1 x = 3 and x = 2 x = -3 and x = -2
@Squirrels
Ok so what you want to do, is put the equation in quadratic form, which looks like this \[ax^2+bx+c=0\]
Do you know what to do next? or do you need help?
I need help please
ok so the equation is \[x^2+5x=-6\] Thats what it looks like right?
Correct.
ok cool, so what we need to do is make into quadratic form but isolating, so we add 6 by both sides. \[x^2+5x+6=0\] See what i did there?
Yeah I do
Ok so now it is in quadratic form. Do you see what i mean? \[ax^2+bx+c=0\] \[1x^2+5x+6=0\]
yes
ok now that we have it in quadratic form we plug it into the "quadraric formula" \[x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\] You wanna plug those in for me?
Or do you get what im saying? ;P
yes I et you after I plug those in what do it do?
You solve it, here let me write it for you and then you solve it, deal?
ok
\[x=\frac{ -5\pm \sqrt{5^2-4 \times 1\times6} }{ 2\times1 }\]
ok there ya go, solve that for me and ill tell you if youre right
im going to say c
am I right?
Youre guessing dude -_- . Its not that hard too figure out. Its simple math.
how is it not c...
the bottom of the equation equals 2 positive and theres only one answer with positive 2
im not guessing im sorry, im really dumb when it comes to math
Its not that. You guess that answer in less then a minute. and thats not who you solve it .-.
how* not who
okay well I finished it just the basic stuff and I got x = -5 + over the _ 1 on top of 3
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