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Physics 9 Online
OpenStudy (anonymous):

How much time does is needed for a car to accelerate 8.6 m/s to a speed of 24 m/s if the acceleration is 3.9 m/s^2?

OpenStudy (abhisar):

Hello @taelyr01 ! \(\Huge{\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}\color{orange}{\bigstar}\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}\color{orange}{\bigstar}\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}}\\\color{white}{.}\\\Huge\color{blue}{\mathfrak{~~~~Welcome~to~OpenStudy!~\ddot\smile}}\\\color{white}{.}\\\\\Huge{\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}\color{orange}{\bigstar}\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}\color{orange}{\bigstar}\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}}\)

OpenStudy (abhisar):

Here initial velocity u is given 8.6, Final velocity v is given 24 m/s, acceleration a is given 3.9 use the equation v=u+at and find the value of t

OpenStudy (anonymous):

3.95 seconds

OpenStudy (abhisar):

@sbsingh Don't provide someone with just the answer - explain the process, and help guide them through understanding the problem. Seeking/Giving Just/Direct Answers is against the \(\large\sf\color{red}{\underline{\href{ /code-of-conduct}{CODE~OF~CONDUCT}}}\)

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