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Mathematics 16 Online
OpenStudy (anonymous):

A rectangular playground is to be fenced off and divided in two by another fence parallel to one side of the playground.544 feet of fencing is used. Find the dimensions of the playground that maximize the total enclosed area. Remember to reduce any fractions and simplify your answers as much as possible. HINT: Start by drawing a picture that illustrates what is being described in the problem, then label the important parts.

OpenStudy (anonymous):

the shorter side of the playground is _____ ft the longer side of the playground is ____ ft what is the maximum area?

OpenStudy (anonymous):

give me two minutes

OpenStudy (anonymous):

THANK YOU!!!! Finally somebody responds!

OpenStudy (anonymous):

k wait, i did this, then i though of a better way, sorry one more minute

OpenStudy (anonymous):

okay thanks!

OpenStudy (anonymous):

k so, shorter side is 77.71, longer side is 155.42, and maximum area is 12,007 but if you have a minute, i'll try to get someone to check it

OpenStudy (anonymous):

@zepdrix will you check this for me?

OpenStudy (anonymous):

@mathstudent55 can you look at this for me?

OpenStudy (anonymous):

@dan815 will you look at this for me?

OpenStudy (anonymous):

those answers are incorrect

OpenStudy (anonymous):

there are three other people viewing this, if any of them could help that'd be great

OpenStudy (anonymous):

sorry bout that, i'm trying to get people *hint, hint*

zepdrix (zepdrix):

Hmm I don't remember how to do maximization problems without using Calculus :O( What class is this for? Algebra stuff?

OpenStudy (anonymous):

yeah

zepdrix (zepdrix):

Do you have a limited number of guesses or no?

zepdrix (zepdrix):

Oh you logged off... awesome..

OpenStudy (anonymous):

@zepdrix thanks for looking at this for me, i didn't think i was doing it right, but i didn't want to leave her hanging:/

zepdrix (zepdrix):

I came up with your numbers the first time I tried it^ I was assuming both areas would have to be square to maximize it. But I guess something else is going on. I came up with some answers using calculus methods. But I guess she's not around the check them :d oh well.

OpenStudy (anonymous):

Ok, thats what i was thinking too and then I tried it where the entire area was square and there was a parallel fence cutting it into two rectangles, but that had a smaller area, so i wasn't sure:) yeah, oh well

zepdrix (zepdrix):

haha yah i tried that too XD too funny!

OpenStudy (nikato):

OMG, you wouldnt believe what i just did. GUESS AND CHECK ALL THE WAY

zepdrix (zepdrix):

0_o

OpenStudy (nikato):

and so far, the biggest area is with sides 90.9 and 135.65

zepdrix (zepdrix):

Ooo nice. I came up with 90.6666 and 136 for the side lengths. So ya you're probably on the right track.

OpenStudy (nikato):

|dw:1406080771300:dw| so \[3x + 2y \le 544\]

zepdrix (zepdrix):

You labeled the vertical lengths x? AHHHH!!

zepdrix (zepdrix):

>.<

OpenStudy (nikato):

yea. they should be the same lengths. two that are the same and three that are the same

OpenStudy (nikato):

then i graphed it and started pluggin points into that equation

OpenStudy (anonymous):

well, I didn't think of doing that :/

OpenStudy (anonymous):

Sorry I lost wifi!!!

OpenStudy (anonymous):

But thank you so so much!

OpenStudy (anonymous):

That makes total sense

OpenStudy (nikato):

youre welcome!

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