Question

3 squareroot of 2 -5 squareroot of 8 please help!

Answer 1

okay, first you need to simplify \[-5\sqrt{8}\] do you know how to do that?

Answer 2

@kmallum u there?

Answer 3

dont remember! @mkerr017

Answer 4

thats fine, you just seperate it into \[-5\sqrt{2\times4}\] then, since four is a perfect square, you can take it out, by converting it to a 2. Multiply the -5 by the 2 that you took out and you get \[-10\sqrt{2}\]

Answer 5

now we are down to \[3\sqrt{2} -10\sqrt{2}\] since they have the same radical, you can combine the two outside numbers and you end up with \[-7\]

Answer 6

sorry, \[-7\sqrt{2}\]

Answer 7

ohh i see thank you! @mkerr017

Answer 8

no problem:) let me know if you have any more questions

Answer 9

how about, 2 squareroot45 - squareroot 80 + 3 squareroot 20

Answer 10

do you want explanation, or just answer?

Answer 11

explaination.. im just a bit off on the coefficient .. the base is squareroot 5.. and thats correct.. the answer is supposed to be 8 squareroot 5

Answer 12

K, so the first thing to look at is that the radical for all of these is different and we need to get them to be the same. By looking i can see that i can get them down to 5. I'll take 9 out of the first one, 16 out of the second, and 4 out of the third leaving me with \[6\sqrt{5}\]\[-4\sqrt{5}\] and \[6\sqrt{5}\] then I simply combine them to get \[8\sqrt{5}\] like you said:)

Answer 13

( 5 squareroot of 2) ^2 - (6 squareroot of 3) ^2 ? :)

Answer 14

sorry, i don't know how to do this one:(