Question

4. Box A contains 8 red and 6 blue tokens. Box B contains 5 red and 11 blue tokens. One token is randomly taken from each box.
a) What is the probability of getting a blue token from Box A and a red token from Box B?
b) What is the probability of getting a blue token and a red token?
c) What is the probability that both tokens are of the same colour?

Answer 1

a) The probability of getting a blue token from box A is 6/14, and the probability of getting a red token from box B is 5/16. The two events are independent, therefore the probability of both occurring is:
\[\frac{6\times5}{14\times16}=you\ can\ calculate\]

Answer 2

83/112.
How about part b?

Answer 3

For part a), how did you get 83 for the numerator of your proposed answer?

Answer 4

oops it's actually 15/112.

Answer 5

Correct!
b) The probability of getting a red token from box A and a blue token from box B is:
\[\frac{8\times11}{14\times16}=you\ can\ calculate\]
When you have found this probability, add it to the value of probability for part a). This is done because the two events, 'blue A / red B' and 'red A / blue B', are mutually exclusive.

Answer 6

59/112?
Thanks!

Answer 7

You're welcome :)

Answer 8

c) You need to work out the probabilities of 'blue A / blue B' and 'red A / red B', and then add them.

Answer 9

mind being more specific? I don't get it...

Answer 10

is it 53/112?

Answer 11

P(blue A) = 6/14
P(blue B) = 11/16
\[P(blue\ A /\ blue\ B)=\frac{6\times11}{14\times16}\]

P(red A) = 8/14
P(red B) = 5/16
\[P(red\ A\ /\ red\ B)=\frac{8\times5}{14\times16}\]
P('blue A / blue B' or 'red A / red B') is given by:
\[(\frac{6\times11}{14\times16})+(\frac{8\times5}{14\times16})=you\ can\ calculate\]

Answer 12

Your answer is correct!