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what is the radius of a circle with the equation x^2+y^2+2x+4y-9=0?
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\(x^2+2x+y^2+4y-9=0\\(x+1)^2-1+(y+2)^2-4-9=0\\(x+1)^2+(y+2)^2=14\)
so the radius is 14?
now use the equation of a circle to get the radius I completed the square two times...
what is the equation of a circle?
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check that link
(x+h)^2+(y-k)^2=r^2
so we have r^2 = 14 what is r?
\[\sqrt{14}\]
it is important that you see how I did this problem, do you?
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i guess its sqrt(14)
or 196
what is 196?
nevermind i guess its square root of 14 but it also says to put the answer into the nearest thousand form
so is it 3.472 ?
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if thats what your calculator says...
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