Question

A customer from Cavallaro's Fruit Stand picks a sample of 5 oranges at random from a crate containing 65 oranges, of which 6 are rotten. What is the probability that the sample contains 1 or more rotten oranges? (Round your answer to three decimal places.

Answer 1

P(zero rotten) + P(1 or more rotten) = 1
Therefore if we find the probability of no rotten fruit in the sample, and subtract that probability from 1 we will have the required probability.
Do you follow so far?

Answer 2

yes

Answer 3

Good.
\[P(0\ rotten)=\frac{C(6, 0) \times C(59, 5)}{C(65, 5)}=you\ can\ calculate\]

Answer 4

1.6498

Answer 5

Not really. For a start the value of probability can never be more than 1. Are you using a calculator to find the value?

Answer 6

yes

Answer 7

0.606

Answer 8

Right. Can you tell me the value of:
C(6, 0) * C(59, 5) = ?

Answer 9

1*5006386

Answer 10

Correct! No the value of:
C(65, 5) = ?

Answer 11

8259888

Answer 12

Correct again! So
\[P(0\ rotten)=\frac{5006386}{8259888}=you\ can\ calculate\]

Answer 13

0.606

Answer 14

Correct! Therefore we get:
P(one or more rotten) = 1.000 - 0.606 = ?

Answer 15

0.394

Answer 16

That is what I get also.

Answer 17

thank you : )

Answer 18

You're welcome :)