Question

Solve x2 + 8x – 48 = 0 by completing the square.

Answer 1

@alg2help

Answer 2

Ppsh, who uses completing the square

Answer 3

well you can use the factor 12 and - 4 so you can get 8
so the simplified verion will be (x + 12)(x - 4)

Answer 4

quadratic equation!!!!!!

Answer 5

completing the square is by far the best imo

for \(x^2+bx+c=0\) we have \((x+\frac{b}{2})^2=-c+(\frac{b}{2})^2\)

Answer 6

No way, completing the squares is the most confusing way there is!

Answer 7

first of all lets make the equation
x^2 + 8x = 48
now we find (b/2)^2
which is 16

add 16 to both sides

x^2 + 8x + 16 = 48 + 16
(x+4)^2 = 64

rad both sides:

x+4 = +-8
x = 4
x = -12

Answer 8

lol thanks everyone! :)

Answer 9

You're welcome - everyone

Answer 10

hehe :)

Answer 11

if the middle term is even and there is no coefficient on the first term, and you practice a few times. You can solve these in your head.

Answer 12

by completing the square....

Answer 13

oh ok

Answer 14

:)

Answer 15

:)

Answer 16

:)

Answer 17

:)