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Mathematics 8 Online
OpenStudy (anonymous):

Solve the Proportion Below and Show How To Solve

OpenStudy (anonymous):

\[k-12 \over k+3 \]= \[4 \over 7\]

OpenStudy (anonymous):

7k-84=4k+12 3k-84=12 3k=96 k=32

OpenStudy (anonymous):

Thanks for the medal

OpenStudy (anonymous):

No prob bro

OpenStudy (anonymous):

if you need anymore help let me know i like helping with proportions :)

OpenStudy (anonymous):

lol ok what about \[x-1 \over 2\] = \[x-6 \over 7\]

OpenStudy (anonymous):

2x-12=7x-7 -5x-12=-7 -5x=5 x=-1

OpenStudy (anonymous):

wait, do i write that as a fraction or like that :?

OpenStudy (anonymous):

only fractions should be when you set up the proportion after you set up the proportion you cross multiply and make it into an equation get x's on one side and numbers on the other then divide numbers by x's

OpenStudy (anonymous):

oh ok thanks um what about \[x-8 \over 2\]=\[x-12 \over 12\]

OpenStudy (anonymous):

12x-98=2x-24 10x-98=-24 10x=74 x=7.4

OpenStudy (anonymous):

thanks, i hope tomorrow you can help me :) i got like 5 more

OpenStudy (anonymous):

one more?

OpenStudy (anonymous):

alright :)

OpenStudy (anonymous):

\[n+9 \over n-10\]=\[\frac{ 6 }{ 10 }\]

OpenStudy (anonymous):

10n+90=6n-60 4n+90=-60 4n=-150 n=37.5

OpenStudy (anonymous):

you seem like your enjoying this, do you wanna just do the other 6? :S

OpenStudy (anonymous):

i can help but cant give answers like i did above someone reported and got warned 3 times today

OpenStudy (anonymous):

ill lead you to the last step then have you do the final step

OpenStudy (anonymous):

ok um, the next one is \[2 \over m-2\]=\[5 \over m-4\]

OpenStudy (anonymous):

2m-8=5m-10 -3m-8=-10 -3m=-2 whats -2 divided by -3?

OpenStudy (anonymous):

0.67

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

ok the next is \[8 \over p-6\]=\[-11 \over -p-5\]

OpenStudy (anonymous):

-11p+66=-8p-40 -3p+66=-40 -3p=-106 whats 106 divided by -3?

OpenStudy (anonymous):

-35.3 :D

OpenStudy (anonymous):

yes :)

OpenStudy (anonymous):

@AravindG this better? :)

OpenStudy (anonymous):

ok the next one is \[x-7 \over x+9\]=\[3 \over 6\]

OpenStudy (aravindg):

No it is sad. You just gave that person all the answers :/

OpenStudy (anonymous):

not all i stopped after you warned me 3 or 4 times just led him to the final step

OpenStudy (aravindg):

Oh I thought the initial answers were after your warning.

OpenStudy (anonymous):

3x+27=6x-42 -3x+27=-42 -3x=-69 whats -69 divided by -3

OpenStudy (anonymous):

23 i belive

OpenStudy (anonymous):

nah that was not long before

OpenStudy (anonymous):

correct

OpenStudy (anonymous):

ok the next equation is \[n-2 \over 11\]= \[n+5 \over 7\]

OpenStudy (anonymous):

7n-14=11n+55 -4n-14=55 -4n=69 whats 69 divided by -4

OpenStudy (anonymous):

-17.25 :D

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

@AravindG while your here i have a question for you

OpenStudy (anonymous):

ok well the next one is \[6 \over b-4\] = \[11 \over b+1\]

OpenStudy (anonymous):

thanks for helping me btw

OpenStudy (anonymous):

6b+6=11b-44 -5b=-50 whats 50 divided by-5

OpenStudy (anonymous):

you're welcome :) i love proportions

OpenStudy (anonymous):

-10 i think :/

OpenStudy (anonymous):

would it stay negative or turn positive?

OpenStudy (anonymous):

stay negative

OpenStudy (anonymous):

2 negatives stay a negative?

OpenStudy (anonymous):

? but you put 50 divided by -5

OpenStudy (anonymous):

oh my bad -50 divided by -5 >.<

OpenStudy (anonymous):

XD oh ok lol

OpenStudy (anonymous):

LAST QUESTION! \[6 \over r-10\] = \[-9 \over r-5\]

OpenStudy (anonymous):

-9r+90=6r-30 -3r+90=-30 -3r=-120 whats -120 divided by -3?

OpenStudy (anonymous):

40 :D all done

OpenStudy (anonymous):

alright hope that helped and all correct :)

OpenStudy (anonymous):

YAY, your a life saver

OpenStudy (anonymous):

:)

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