How many grams of zinc metal will react completely with 8.2 liters of 3.5 M HCl? Show all of the work needed to solve this problem. Zn (s) + 2 HCl (aq) yields ZnCl2 (aq) + H2 (g)
See 1litre=1dm3 and M which is molarity is equal to concentration so we know the formula c= n/ v where v is volume c is concentration and n no. Of moles but as we have to find the no.of moles of HCl first so n=c into v that is 8.2 into 3.5 makes 28.7 moles of HCl but as ratio of Zinc to HCl is 1:2 so there will be 14.35 moles of Zinc form and we know the equation for finding mass that is mass= Mr( molecular mass) into no.of moles so molecular mass of zinc is 65.4 which is then multiplied by no of moles 14.35 making 938.49 grams of Zinc form
is there any sig figures?
Yeah rounding off the answer it's 938.5 gm of Zinc form ok
alright i appreciate all your help!!!!
No problem anytime!!!
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